3y-3(y-2)=2(y+1)-6

Solution for 3y-3(y-2)=2(y+1)-6 equation:

Simplifying
3y + -3(y + -2) = 2(y + 1) + -6

Reorder the terms:
3y + -3(-2 + y) = 2(y + 1) + -6
3y + (-2 * -3 + y * -3) = 2(y + 1) + -6
3y + (6 + -3y) = 2(y + 1) + -6

Reorder the terms:
6 + 3y + -3y = 2(y + 1) + -6

Combine like terms: 3y + -3y = 0
6 + 0 = 2(y + 1) + -6
6 = 2(y + 1) + -6

Reorder the terms:
6 = 2(1 + y) + -6
6 = (1 * 2 + y * 2) + -6
6 = (2 + 2y) + -6

Reorder the terms:
6 = 2 + -6 + 2y

Combine like terms: 2 + -6 = -4
6 = -4 + 2y

Solving
6 = -4 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
6 + -2y = -4 + 2y + -2y

Combine like terms: 2y + -2y = 0
6 + -2y = -4 + 0
6 + -2y = -4

Add '-6' to each side of the equation.
6 + -6 + -2y = -4 + -6

Combine like terms: 6 + -6 = 0
0 + -2y = -4 + -6
-2y = -4 + -6

Combine like terms: -4 + -6 = -10
-2y = -10

Divide each side by '-2'.
y = 5

Simplifying
y = 5