3y-3(y-1)=7-(3y-4)-11

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Solution for 3y-3(y-1)=7-(3y-4)-11 equation: 



3y-3(y-1)=7-(3y-4)-11

We move all terms to the left:

3y-3(y-1)-(7-(3y-4)-11)=0

We multiply parentheses

3y-3y-(7-(3y-4)-11)+3=0



We calculate terms in parentheses: -(7-(3y-4)-11), so:

7-(3y-4)-11

determiningTheFunctionDomain
-(3y-4)+7-11

We add all the numbers together, and all the variables

-(3y-4)-4

We get rid of parentheses

-3y+4-4

We add all the numbers together, and all the variables

-3y

Back to the equation:

-(-3y)



We add all the numbers together, and all the variables

-(-3y)+3=0

We get rid of parentheses

3y+3=0

We move all terms containing y to the left, all other terms to the right

3y=-3

y=-3/3

y=-1

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