3y-2=13y+38

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Solution for 3y-2=13y+38 equation: 



3y-2=13y+38

We move all terms to the left:

3y-2-(13y+38)=0

We get rid of parentheses

3y-13y-38-2=0

We add all the numbers together, and all the variables

-10y-40=0

We move all terms containing y to the left, all other terms to the right

-10y=40

y=40/-10

y=-4

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