3y-20=-2(y-5)

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Solution for 3y-20=-2(y-5) equation: 



3y-20=-2(y-5)

We move all terms to the left:

3y-20-(-2(y-5))=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We get rid of parentheses

3y+2y-10-20=0

We add all the numbers together, and all the variables

5y-30=0

We move all terms containing y to the left, all other terms to the right

5y=30

y=30/5

y=6

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