3y-2+3y-5=2y+10

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Solution for 3y-2+3y-5=2y+10 equation: 



3y-2+3y-5=2y+10

We move all terms to the left:

3y-2+3y-5-(2y+10)=0

We add all the numbers together, and all the variables

6y-(2y+10)-7=0

We get rid of parentheses

6y-2y-10-7=0

We add all the numbers together, and all the variables

4y-17=0

We move all terms containing y to the left, all other terms to the right

4y=17

y=17/4

y=4+1/4

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