3y-2(4y-5)=3-5(-1-y)

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Solution for 3y-2(4y-5)=3-5(-1-y) equation: 



3y-2(4y-5)=3-5(-1-y)

We move all terms to the left:

3y-2(4y-5)-(3-5(-1-y))=0

We add all the numbers together, and all the variables

3y-2(4y-5)-(3-5(-1y-1))=0

We multiply parentheses

3y-8y-(3-5(-1y-1))+10=0



We calculate terms in parentheses: -(3-5(-1y-1)), so:

3-5(-1y-1)

determiningTheFunctionDomain
-5(-1y-1)+3

We multiply parentheses

5y+5+3

We add all the numbers together, and all the variables

5y+8

Back to the equation:

-(5y+8)



We add all the numbers together, and all the variables

-5y-(5y+8)+10=0

We get rid of parentheses

-5y-5y-8+10=0

We add all the numbers together, and all the variables

-10y+2=0

We move all terms containing y to the left, all other terms to the right

-10y=-2

y=-2/-10

y=1/5

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