3y-2(3y-5)=19

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Solution for 3y-2(3y-5)=19 equation: 



3y-2(3y-5)=19

We move all terms to the left:

3y-2(3y-5)-(19)=0

We multiply parentheses

3y-6y+10-19=0

We add all the numbers together, and all the variables

-3y-9=0

We move all terms containing y to the left, all other terms to the right

-3y=9

y=9/-3

y=-3

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