3y-12=6(y+3)

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Solution for 3y-12=6(y+3) equation: 



3y-12=6(y+3)

We move all terms to the left:

3y-12-(6(y+3))=0



We calculate terms in parentheses: -(6(y+3)), so:

6(y+3)

We multiply parentheses

6y+18

Back to the equation:

-(6y+18)



We get rid of parentheses

3y-6y-18-12=0

We add all the numbers together, and all the variables

-3y-30=0

We move all terms containing y to the left, all other terms to the right

-3y=30

y=30/-3

y=-10

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