3y-(2y-7)=9y-3(2y-4)

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Solution for 3y-(2y-7)=9y-3(2y-4) equation: 



3y-(2y-7)=9y-3(2y-4)

We move all terms to the left:

3y-(2y-7)-(9y-3(2y-4))=0

We get rid of parentheses

3y-2y-(9y-3(2y-4))+7=0



We calculate terms in parentheses: -(9y-3(2y-4)), so:

9y-3(2y-4)

We multiply parentheses

9y-6y+12

We add all the numbers together, and all the variables

3y+12

Back to the equation:

-(3y+12)



We add all the numbers together, and all the variables

y-(3y+12)+7=0

We get rid of parentheses

y-3y-12+7=0

We add all the numbers together, and all the variables

-2y-5=0

We move all terms containing y to the left, all other terms to the right

-2y=5

y=5/-2

y=-2+1/2

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