3y+y2-y+7y+2y=2

Solution for 3y+y2-y+7y+2y=2 equation:

3y+y2-y+7y+2y=2

We move all terms to the left:

3y+y2-y+7y+2y-(2)=0

We add all the numbers together, and all the variables

y^2+11y-2=0

a = 1; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·1·(-2)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{129}}{2*1}=\frac{-11-\sqrt{129}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{129}}{2*1}=\frac{-11+\sqrt{129}}{2}
$