3y+70+3(y-1)=2(2y+6)

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Solution for 3y+70+3(y-1)=2(2y+6) equation: 



3y+70+3(y-1)=2(2y+6)

We move all terms to the left:

3y+70+3(y-1)-(2(2y+6))=0

We multiply parentheses

3y+3y-(2(2y+6))-3+70=0



We calculate terms in parentheses: -(2(2y+6)), so:

2(2y+6)

We multiply parentheses

4y+12

Back to the equation:

-(4y+12)



We add all the numbers together, and all the variables

6y-(4y+12)+67=0

We get rid of parentheses

6y-4y-12+67=0

We add all the numbers together, and all the variables

2y+55=0

We move all terms containing y to the left, all other terms to the right

2y=-55

y=-55/2

y=-27+1/2

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