3y+7-2(-3y-1)=3(y-2)

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Solution for 3y+7-2(-3y-1)=3(y-2) equation: 



3y+7-2(-3y-1)=3(y-2)

We move all terms to the left:

3y+7-2(-3y-1)-(3(y-2))=0

We multiply parentheses

3y+6y-(3(y-2))+2+7=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We add all the numbers together, and all the variables

9y-(3y-6)+9=0

We get rid of parentheses

9y-3y+6+9=0

We add all the numbers together, and all the variables

6y+15=0

We move all terms containing y to the left, all other terms to the right

6y=-15

y=-15/6

y=-2+1/2

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