3y+57=7y-19

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Solution for 3y+57=7y-19 equation: 



3y+57=7y-19

We move all terms to the left:

3y+57-(7y-19)=0

We get rid of parentheses

3y-7y+19+57=0

We add all the numbers together, and all the variables

-4y+76=0

We move all terms containing y to the left, all other terms to the right

-4y=-76

y=-76/-4

y=+19

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