3y+4=2(-y-3)

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Solution for 3y+4=2(-y-3) equation: 



3y+4=2(-y-3)

We move all terms to the left:

3y+4-(2(-y-3))=0

We add all the numbers together, and all the variables

3y-(2(-1y-3))+4=0



We calculate terms in parentheses: -(2(-1y-3)), so:

2(-1y-3)

We multiply parentheses

-2y-6

Back to the equation:

-(-2y-6)



We get rid of parentheses

3y+2y+6+4=0

We add all the numbers together, and all the variables

5y+10=0

We move all terms containing y to the left, all other terms to the right

5y=-10

y=-10/5

y=-2

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