3y+3=3(-y+5)

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Solution for 3y+3=3(-y+5) equation: 



3y+3=3(-y+5)

We move all terms to the left:

3y+3-(3(-y+5))=0

We add all the numbers together, and all the variables

3y-(3(-1y+5))+3=0



We calculate terms in parentheses: -(3(-1y+5)), so:

3(-1y+5)

We multiply parentheses

-3y+15

Back to the equation:

-(-3y+15)



We get rid of parentheses

3y+3y-15+3=0

We add all the numbers together, and all the variables

6y-12=0

We move all terms containing y to the left, all other terms to the right

6y=12

y=12/6

y=2

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