3y+33=-6(y-7)

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Solution for 3y+33=-6(y-7) equation: 



3y+33=-6(y-7)

We move all terms to the left:

3y+33-(-6(y-7))=0



We calculate terms in parentheses: -(-6(y-7)), so:

-6(y-7)

We multiply parentheses

-6y+42

Back to the equation:

-(-6y+42)



We get rid of parentheses

3y+6y-42+33=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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