3y+3-4(-3y-1)=3(y-1)

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Solution for 3y+3-4(-3y-1)=3(y-1) equation: 



3y+3-4(-3y-1)=3(y-1)

We move all terms to the left:

3y+3-4(-3y-1)-(3(y-1))=0

We multiply parentheses

3y+12y-(3(y-1))+4+3=0



We calculate terms in parentheses: -(3(y-1)), so:

3(y-1)

We multiply parentheses

3y-3

Back to the equation:

-(3y-3)



We add all the numbers together, and all the variables

15y-(3y-3)+7=0

We get rid of parentheses

15y-3y+3+7=0

We add all the numbers together, and all the variables

12y+10=0

We move all terms containing y to the left, all other terms to the right

12y=-10

y=-10/12

y=-5/6

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