3y+2=y+22(y-1)+4

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Solution for 3y+2=y+22(y-1)+4 equation: 



3y+2=y+22(y-1)+4

We move all terms to the left:

3y+2-(y+22(y-1)+4)=0



We calculate terms in parentheses: -(y+22(y-1)+4), so:

y+22(y-1)+4

We multiply parentheses

y+22y-22+4

We add all the numbers together, and all the variables

23y-18

Back to the equation:

-(23y-18)



We get rid of parentheses

3y-23y+18+2=0

We add all the numbers together, and all the variables

-20y+20=0

We move all terms containing y to the left, all other terms to the right

-20y=-20

y=-20/-20

y=1

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