3y+22+4y=100

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Solution for 3y+22+4y=100 equation: 



3y+22+4y=100

We move all terms to the left:

3y+22+4y-(100)=0

We add all the numbers together, and all the variables

7y-78=0

We move all terms containing y to the left, all other terms to the right

7y=78

y=78/7

y=11+1/7

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