3y+2(y-8)=7y-4(y-10)

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Solution for 3y+2(y-8)=7y-4(y-10) equation:


Simplifying
3y + 2(y + -8) = 7y + -4(y + -10)

Reorder the terms:
3y + 2(-8 + y) = 7y + -4(y + -10)
3y + (-8 * 2 + y * 2) = 7y + -4(y + -10)
3y + (-16 + 2y) = 7y + -4(y + -10)

Reorder the terms:
-16 + 3y + 2y = 7y + -4(y + -10)

Combine like terms: 3y + 2y = 5y
-16 + 5y = 7y + -4(y + -10)

Reorder the terms:
-16 + 5y = 7y + -4(-10 + y)
-16 + 5y = 7y + (-10 * -4 + y * -4)
-16 + 5y = 7y + (40 + -4y)

Reorder the terms:
-16 + 5y = 40 + 7y + -4y

Combine like terms: 7y + -4y = 3y
-16 + 5y = 40 + 3y

Solving
-16 + 5y = 40 + 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
-16 + 5y + -3y = 40 + 3y + -3y

Combine like terms: 5y + -3y = 2y
-16 + 2y = 40 + 3y + -3y

Combine like terms: 3y + -3y = 0
-16 + 2y = 40 + 0
-16 + 2y = 40

Add '16' to each side of the equation.
-16 + 16 + 2y = 40 + 16

Combine like terms: -16 + 16 = 0
0 + 2y = 40 + 16
2y = 40 + 16

Combine like terms: 40 + 16 = 56
2y = 56

Divide each side by '2'.
y = 28

Simplifying
y = 28

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