3y+18=-4(y-1)

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Solution for 3y+18=-4(y-1) equation: 



3y+18=-4(y-1)

We move all terms to the left:

3y+18-(-4(y-1))=0



We calculate terms in parentheses: -(-4(y-1)), so:

-4(y-1)

We multiply parentheses

-4y+4

Back to the equation:

-(-4y+4)



We get rid of parentheses

3y+4y-4+18=0

We add all the numbers together, and all the variables

7y+14=0

We move all terms containing y to the left, all other terms to the right

7y=-14

y=-14/7

y=-2

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