3y+12=3*(4+y)

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Solution for 3y+12=3*(4+y) equation: 



3y+12=3(4+y)

We move all terms to the left:

3y+12-(3(4+y))=0

We add all the numbers together, and all the variables

3y-(3(y+4))+12=0



We calculate terms in parentheses: -(3(y+4)), so:

3(y+4)

We multiply parentheses

3y+12

Back to the equation:

-(3y+12)



We get rid of parentheses

3y-3y-12+12=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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