3y+12=3(2y-2)

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Solution for 3y+12=3(2y-2) equation: 



3y+12=3(2y-2)

We move all terms to the left:

3y+12-(3(2y-2))=0



We calculate terms in parentheses: -(3(2y-2)), so:

3(2y-2)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

3y-6y+6+12=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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