3y+(y-3)=125

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Solution for 3y+(y-3)=125 equation: 



3y+(y-3)=125

We move all terms to the left:

3y+(y-3)-(125)=0

We get rid of parentheses

3y+y-3-125=0

We add all the numbers together, and all the variables

4y-128=0

We move all terms containing y to the left, all other terms to the right

4y=128

y=128/4

y=32

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