3y+(y-2)=2(2y-1)

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Solution for 3y+(y-2)=2(2y-1) equation:


Simplifying
3y + (y + -2) = 2(2y + -1)

Reorder the terms:
3y + (-2 + y) = 2(2y + -1)

Remove parenthesis around (-2 + y)
3y + -2 + y = 2(2y + -1)

Reorder the terms:
-2 + 3y + y = 2(2y + -1)

Combine like terms: 3y + y = 4y
-2 + 4y = 2(2y + -1)

Reorder the terms:
-2 + 4y = 2(-1 + 2y)
-2 + 4y = (-1 * 2 + 2y * 2)
-2 + 4y = (-2 + 4y)

Add '2' to each side of the equation.
-2 + 2 + 4y = -2 + 2 + 4y

Combine like terms: -2 + 2 = 0
0 + 4y = -2 + 2 + 4y
4y = -2 + 2 + 4y

Combine like terms: -2 + 2 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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