3y*5+2=4+(9y*3)-50

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Solution for 3y*5+2=4+(9y*3)-50 equation: 



3y*5+2=4+(9y*3)-50

We move all terms to the left:

3y*5+2-(4+(9y*3)-50)=0

We add all the numbers together, and all the variables

3y*5-(4+(+9y*3)-50)+2=0

Wy multiply elements

15y-(4+(+9y*3)-50)+2=0



We calculate terms in parentheses: -(4+(+9y*3)-50), so:

4+(+9y*3)-50

determiningTheFunctionDomain
(+9y*3)+4-50

We add all the numbers together, and all the variables

(+9y*3)-46

We get rid of parentheses

9y*3-46

Wy multiply elements

27y-46

Back to the equation:

-(27y-46)



We get rid of parentheses

15y-27y+46+2=0

We add all the numbers together, and all the variables

-12y+48=0

We move all terms containing y to the left, all other terms to the right

-12y=-48

y=-48/-12

y=+4

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