3x=5+-2(3x+4x)

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Solution for 3x=5+-2(3x+4x) equation: 



3x=5+-2(3x+4x)

We move all terms to the left:

3x-(5+-2(3x+4x))=0

We add all the numbers together, and all the variables

3x-(5+-2(+7x))=0

We use the square of the difference formula

3x-(5-2(+7x))=0



We calculate terms in parentheses: -(5-2(+7x)), so:

5-2(+7x)

determiningTheFunctionDomain
-2(+7x)+5

We multiply parentheses

-14x+5

Back to the equation:

-(-14x+5)



We get rid of parentheses

3x+14x-5=0

We add all the numbers together, and all the variables

17x-5=0

We move all terms containing x to the left, all other terms to the right

17x=5

x=5/17

x=5/17

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