3x=5+-2(3+4x)

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Solution for 3x=5+-2(3+4x) equation: 



3x=5+-2(3+4x)

We move all terms to the left:

3x-(5+-2(3+4x))=0

We add all the numbers together, and all the variables

3x-(5+-2(4x+3))=0

We use the square of the difference formula

3x-(5-2(4x+3))=0



We calculate terms in parentheses: -(5-2(4x+3)), so:

5-2(4x+3)

determiningTheFunctionDomain
-2(4x+3)+5

We multiply parentheses

-8x-6+5

We add all the numbers together, and all the variables

-8x-1

Back to the equation:

-(-8x-1)



We get rid of parentheses

3x+8x+1=0

We add all the numbers together, and all the variables

11x+1=0

We move all terms containing x to the left, all other terms to the right

11x=-1

x=-1/11

x=-1/11

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