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3x=4x(x-2.25)
We move all terms to the left:
3x-(4x(x-2.25))=0
We calculate terms in parentheses: -(4x(x-2.25)), so:We get rid of parentheses
4x(x-2.25)
We multiply parentheses
4x^2-9x
Back to the equation:
-(4x^2-9x)
-4x^2+3x+9x=0
We add all the numbers together, and all the variables
-4x^2+12x=0
a = -4; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-4)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-4}=\frac{-24}{-8} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-4}=\frac{0}{-8} =0 $
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