3x=40+(x+30)

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Solution for 3x=40+(x+30) equation: 



3x=40+(x+30)

We move all terms to the left:

3x-(40+(x+30))=0



We calculate terms in parentheses: -(40+(x+30)), so:

40+(x+30)

determiningTheFunctionDomain
(x+30)+40

We get rid of parentheses

x+30+40

We add all the numbers together, and all the variables

x+70

Back to the equation:

-(x+70)



We get rid of parentheses

3x-x-70=0

We add all the numbers together, and all the variables

2x-70=0

We move all terms containing x to the left, all other terms to the right

2x=70

x=70/2

x=35

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