3x=40+(x+15)

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Solution for 3x=40+(x+15) equation:



3x=40+(x+15)
We move all terms to the left:
3x-(40+(x+15))=0
We calculate terms in parentheses: -(40+(x+15)), so:
40+(x+15)
determiningTheFunctionDomain (x+15)+40
We get rid of parentheses
x+15+40
We add all the numbers together, and all the variables
x+55
Back to the equation:
-(x+55)
We get rid of parentheses
3x-x-55=0
We add all the numbers together, and all the variables
2x-55=0
We move all terms containing x to the left, all other terms to the right
2x=55
x=55/2
x=27+1/2

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