3x=35+1/2x

Solution for 3x=35+1/2x equation:

3x=35+1/2x

We move all terms to the left:

3x-(35+1/2x)=0


Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x-(1/2x+35)=0

We get rid of parentheses

3x-1/2x-35=0

We multiply all the terms by the denominator


3x*2x-35*2x-1=0

Wy multiply elements

6x^2-70x-1=0

a = 6; b = -70; c = -1;
Δ = b2-4ac
Δ = -702-4·6·(-1)
Δ = 4924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4924}=\sqrt{4*1231}=\sqrt{4}*\sqrt{1231}=2\sqrt{1231}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1231}}{2*6}=\frac{70-2\sqrt{1231}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1231}}{2*6}=\frac{70+2\sqrt{1231}}{12}
$