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3x=20+(x-30/2)
We move all terms to the left:
3x-(20+(x-30/2))=0
We add all the numbers together, and all the variables
3x-(20+(x-15))=0
We calculate terms in parentheses: -(20+(x-15)), so:We get rid of parentheses
20+(x-15)
determiningTheFunctionDomain (x-15)+20
We get rid of parentheses
x-15+20
We add all the numbers together, and all the variables
x+5
Back to the equation:
-(x+5)
3x-x-5=0
We add all the numbers together, and all the variables
2x-5=0
We move all terms containing x to the left, all other terms to the right
2x=5
x=5/2
x=2+1/2
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