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3x=20(x+6)/7
We move all terms to the left:
3x-(20(x+6)/7)=0
We multiply all the terms by the denominator
3x*7)-(20(x+6)=0
Wy multiply elements
21x^2=0
a = 21; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·21·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{42}=0$
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