3x=14(x-4)/5

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Solution for 3x=14(x-4)/5 equation: 



3x=14(x-4)/5

We move all terms to the left:

3x-(14(x-4)/5)=0

We multiply all the terms by the denominator


3x*5)-(14(x-4)=0

Wy multiply elements

15x^2=0

a = 15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·15·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{30}=0$

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