3x=(x+3)-3(x-3)

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Solution for 3x=(x+3)-3(x-3) equation: 



3x=(x+3)-3(x-3)

We move all terms to the left:

3x-((x+3)-3(x-3))=0



We calculate terms in parentheses: -((x+3)-3(x-3)), so:

(x+3)-3(x-3)

We multiply parentheses

(x+3)-3x+9

We get rid of parentheses

x-3x+3+9

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We get rid of parentheses

3x+2x-12=0

We add all the numbers together, and all the variables

5x-12=0

We move all terms containing x to the left, all other terms to the right

5x=12

x=12/5

x=2+2/5

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