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3x^2=2(x-1)
We move all terms to the left:
3x^2-(2(x-1))=0
We calculate terms in parentheses: -(2(x-1)), so:We get rid of parentheses
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
3x^2-2x+2=0
a = 3; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·3·2
Δ = -20
Delta is less than zero, so there is no solution for the equation
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