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3x^2=1728
We move all terms to the left:
3x^2-(1728)=0
a = 3; b = 0; c = -1728;
Δ = b2-4ac
Δ = 02-4·3·(-1728)
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*3}=\frac{-144}{6} =-24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*3}=\frac{144}{6} =24 $
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