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3x^2-80-400=0
We add all the numbers together, and all the variables
3x^2-480=0
a = 3; b = 0; c = -480;
Δ = b2-4ac
Δ = 02-4·3·(-480)
Δ = 5760
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5760}=\sqrt{576*10}=\sqrt{576}*\sqrt{10}=24\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{10}}{2*3}=\frac{0-24\sqrt{10}}{6} =-\frac{24\sqrt{10}}{6} =-4\sqrt{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{10}}{2*3}=\frac{0+24\sqrt{10}}{6} =\frac{24\sqrt{10}}{6} =4\sqrt{10} $
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