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3x^2-50=-5x
We move all terms to the left:
3x^2-50-(-5x)=0
We get rid of parentheses
3x^2+5x-50=0
a = 3; b = 5; c = -50;
Δ = b2-4ac
Δ = 52-4·3·(-50)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-25}{2*3}=\frac{-30}{6} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+25}{2*3}=\frac{20}{6} =3+1/3 $
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