3x2-4x-16500=0

Solution for 3x2-4x-16500=0 equation:

3x^2-4x-16500=0

a = 3; b = -4; c = -16500;
Δ = b2-4ac
Δ = -42-4·3·(-16500)
Δ = 198016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{198016}=\sqrt{64*3094}=\sqrt{64}*\sqrt{3094}=8\sqrt{3094}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{3094}}{2*3}=\frac{4-8\sqrt{3094}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{3094}}{2*3}=\frac{4+8\sqrt{3094}}{6}
$