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3x^2-36x+81=0
a = 3; b = -36; c = +81;
Δ = b2-4ac
Δ = -362-4·3·81
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-18}{2*3}=\frac{18}{6} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+18}{2*3}=\frac{54}{6} =9 $
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