3x2+7x+-24=-13x

Solution for 3x2+7x+-24=-13x equation:

3x^2+7x+-24=-13x

We move all terms to the left:

3x^2+7x+-24-(-13x)=0

We add all the numbers together, and all the variables

3x^2+7x-(-13x)=0

We get rid of parentheses

3x^2+7x+13x=0

We add all the numbers together, and all the variables

3x^2+20x=0

a = 3; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·3·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*3}=\frac{-40}{6}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*3}=\frac{0}{6}
=0
$