3x2+5x=-7x+28

Solution for 3x2+5x=-7x+28 equation:

3x^2+5x=-7x+28

We move all terms to the left:

3x^2+5x-(-7x+28)=0

We get rid of parentheses

3x^2+5x+7x-28=0

We add all the numbers together, and all the variables

3x^2+12x-28=0

a = 3; b = 12; c = -28;
Δ = b2-4ac
Δ = 122-4·3·(-28)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{30}}{2*3}=\frac{-12-4\sqrt{30}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{30}}{2*3}=\frac{-12+4\sqrt{30}}{6}
$