3x2+45x+168=0

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Solution for 3x2+45x+168=0 equation: 



3x^2+45x+168=0

a = 3; b = 45; c = +168;
Δ = b2-4ac
Δ = 452-4·3·168
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-3}{2*3}=\frac{-48}{6}
=-8
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+3}{2*3}=\frac{-42}{6}
=-7
$

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