3x2+3x-16=0

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Solution for 3x2+3x-16=0 equation: 



3x^2+3x-16=0

a = 3; b = 3; c = -16;
Δ = b2-4ac
Δ = 32-4·3·(-16)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{201}}{2*3}=\frac{-3-\sqrt{201}}{6}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{201}}{2*3}=\frac{-3+\sqrt{201}}{6}
$

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