3x2+270x-104000=0

Solution for 3x2+270x-104000=0 equation:

3x^2+270x-104000=0

a = 3; b = 270; c = -104000;
Δ = b2-4ac
Δ = 2702-4·3·(-104000)
Δ = 1320900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1320900}=\sqrt{100*13209}=\sqrt{100}*\sqrt{13209}=10\sqrt{13209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(270)-10\sqrt{13209}}{2*3}=\frac{-270-10\sqrt{13209}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(270)+10\sqrt{13209}}{2*3}=\frac{-270+10\sqrt{13209}}{6}
$