3x2+24x=27

Solution for 3x2+24x=27 equation:

3x^2+24x=27

We move all terms to the left:

3x^2+24x-(27)=0

a = 3; b = 24; c = -27;
Δ = b2-4ac
Δ = 242-4·3·(-27)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-30}{2*3}=\frac{-54}{6}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+30}{2*3}=\frac{6}{6}
=1
$