3x2+19x=154

Solution for 3x2+19x=154 equation:

3x^2+19x=154

We move all terms to the left:

3x^2+19x-(154)=0

a = 3; b = 19; c = -154;
Δ = b2-4ac
Δ = 192-4·3·(-154)
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2209}=47$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-47}{2*3}=\frac{-66}{6}
=-11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+47}{2*3}=\frac{28}{6}
=4+2/3
$