3x2+16x-3584=0

Solution for 3x2+16x-3584=0 equation:

3x^2+16x-3584=0

a = 3; b = 16; c = -3584;
Δ = b2-4ac
Δ = 162-4·3·(-3584)
Δ = 43264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{43264}=208$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-208}{2*3}=\frac{-224}{6}
=-37+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+208}{2*3}=\frac{192}{6}
=32
$